WebTranscribed Image Text: For the function h whose graph is given, state the value of each quantity, if it exists. (If an answer does not exist, enter DNE.) y (a) lim h(x) X→-3- 4 (b) (c) D (f) (d) h(-3) 4 (i) lim x→-3+ 1 e X-3 DNE lim_h(x) (k) x → 0 1 lim h(x) (h) h(0) -1 -4 -2 -1 (g) lim h(x) x → 0 1 lim, h(x) h(x) x → 2 4 (j) h(2) 2 lim_h(x) x+5+ 4.8 lim h(x) (1) lim h(x) x … WebSep 21, 2024 · The graph of y= h(x) is a transformation of the graph of y= g(x) ? Steps please. Thank you . Algebra. 1 Answer Douglas K. Sep 21, 2024 Please consider the point #g(1) = 0#. The same condition occurs at #h(-5)# We can write. #h(-5) = g(1)# We can assert that: #-5 = 1 + k# #k = -6# #h(x) = g(x-6)# ...
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Web(a) The graph of y=h (x) is shown. Draw the graph of y=- h (x+2). (b) The graph of y=g (x) is shown. Draw the graph of y=g (2x)-4. Part (a) Part (b) x 0 ? Previous question Next question Get more help from Chegg Solve it with our algebra problem solver and calculator COMPANY About Chegg Chegg For Good College Marketing Corporate Development WebMar 31, 2024 · Accepted Answer: Reshma Nerella. I am trying to plot Improved Euler's method but I only get an empty graph. I have no idea what is wrong. Here is my code. Theme. Copy. fprintf ('Imp Euler With h=0.1') dy=@ (x,y) … share the love tualatin
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WebHomework help starts here! ASK AN EXPERT. Math Calculus The graph of y = h (x) is a line segment joining the points (1, -5) and (9, 1). Drag the endpoints of the segment below to graph y h (r). The graph of y = h (x) is a line segment joining the points (1, -5) and (9, 1). WebApr 9, 2024 · View Screenshot 2024-04-09 234225.png from MATH 1001 at Chamblee Charter High School. y = f(x) + c graph of (x) translates UP by c units y = f(x) - G graph … WebSep 30, 2024 · The points on the graph of y= h (x) are: (-1,-2), (-2,-4), (0,0), (2,-1), (4,-2) Using the above ordered pairs, the points on y = h (2x) + 1 are: When x = -1, h (2x) = h (-2) = -4 So, we have: y = -4 + 1 = -3 When x = -2, h (2x) = h (-4) = -8 So, we have: y = -8 + 1 = -7 When x = 0, h (2x) = h (0) = 0 So, we have: y = 0 + 1 = 1 poplar kitchen table